10位以内二进制数字转十进制计算器（Printing the Decimal Equivalent of a Binary Number）

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10位以内二进制数字转十进制计算器（Printing the Decimal Equivalent of a Binary Number）

挺有成就感的一个小程序，二进制转十进制。

代码如下：

//JHTP Exercise 4.31: Printing the Decimal Equivalent of a Binary Number //by pandenghuang@163 /*(Printing the Decimal Equivalent of a Binary Number) Write an application that inputs an *integer containing only 0s and 1s (i.e., a binary integer) and prints its decimal equivalent. [Hint: Use *the remainder and division operators to pick off the binary number’s digits one at a time, from right *to left. In the decimal number system, the rightmost digit has a positional value of 1 and the next *digit to the left a positional value of 10, then 100, then 1000, and so on. The decimal number 234 *can be interpreted as 4 * 1 + 3 * 10 + 2 * 100. In the binary number system, the rightmost digit has *a positional value of 1, the next digit to the left a positional value of 2, then 4, then 8, and so on. *The decimal equivalent of binary 1101 is 1 * 1 + 0 * 2 + 1 * 4 + 1 * 8, or 1 + 0 + 4 + 8 or, 13.]*/ import java.util.Scanner; import java.math.*; public class Binary2Decimal { public static void main(String[] args) { int binary=0; int decimal=0; int len=0; int[] binaryDigit=new int[10]; int counter=0; int tempBinary=0; Scanner input=new Scanner(System.in); System.out.print("请输入要转换的二进制数字："); binary=input.nextInt(); tempBinary=binary; //1011 len=String.valueOf(tempBinary).length(); while (counter<len){ binaryDigit[counter]=(int)(tempBinary%10); tempBinary/=10; counter++; } counter=0; //decimal=1*1+1*2+0*2*2+1*2*2*2=11 while (counter<len) { decimal+=binaryDigit[counter]*(int)Math.pow(2, counter); counter++; } System.out.printf("二进制数%d对应的十进制数为： %d",binary,decimal); } }

运行结果：

请输入要转换的二进制数字：1100001110 二进制数1100001110对应的十进制数为： 782

请输入要转换的二进制数字：10011110 二进制数10011110对应的十进制数为： 158



本文标签： 计算器二进制数字转十进制PrintingBinary