基于Python实现可以进制转换和计算阶乘的科学计算器

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基于Python实现可以进制转换和计算阶乘的科学计算器

类似项目 👁

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项目背景⭐️

       本人已经做了两个基于Python的计算器项目，有需要的话，请看本文头部。这次基于Python制作一个科学计算器 项目，创建一个科学计算器。

项目需求💥

1、科学计算器应包括：计算器界面、0-9数字按键、清零和各功能按键； 2、功能1：二进制、八进制、十进制、十六进制、四种进制可相互切换； 3、功能2：加减乘除基本运算、平方、开方、x^y、 x^3等； 4、功能3：tan、cos、sin、n！、log等

代码展示💻 from tkinter import StringVar, Entry, Button from tkinter import Tk import math class calculator: def __init__(self): window = Tk() window.title('基于TK的科学计算器') window.configure(background="white") self.string = StringVar() entry = Entry(window, textvariable=self.string, ) entry.grid(row=0, column=0, columnspan=6) entry.configure(background="white") entry.focus() values = ["C", "DEL", "(", ")", "%", "!", "sin", "sqrt", "e", "pow", "/", "oct", "cos", "7", "8", "9", "*", "int", "tan", "4", "5", "6", "-", "hex", "pi", "1", "2", "3", "+", "bin", "log", ",", "0", ".", "="] text = 1 i = 0 row = 1 col = 0 for txt in values: padx = 10 pady = 10 if (i == 6): row = 2 col = 0 if (i == 12): row = 3 col = 0 if (i == 18): row = 4 col = 0 if (i == 24): row = 5 col = 0 if (i == 30): row = 6 col = 0 if (txt == '='): btn = Button(window, height=2, width=4, padx=50, pady=pady, text=txt, command=lambda txt=txt: self.equals()) btn.grid(row=row, column=col, columnspan=3, padx=2, pady=2) btn.configure(background="yellow") elif (txt == 'DEL'): btn = Button(window, height=2, width=4, padx=padx, pady=pady, text=txt, command=lambda txt=txt: self.delete()) btn.grid(row=row, column=col, padx=1, pady=1) btn.configure(background="grey") elif (txt == 'C'): btn = Button(window, height=2, width=4, padx=padx, pady=pady, text=txt, command=lambda txt=txt: self.clearall()) btn.grid(row=row, column=col, padx=1, pady=1) btn.configure(background="red") else: btn = Button(window, height=2, width=4, padx=padx, pady=pady, text=txt, command=lambda txt=txt: self.addChar(txt)) btn.grid(row=row, column=col, padx=1, pady=1) btn.configure(background="white") col = col + 1 i = i + 1 window.mainloop() def fac(self): n = int(self.string.get()[0:1]) print(n) num = 1 if n < 0: print('负数没有阶乘！') elif n == 0: print('0的阶乘为1！') else: for i in range(1, n + 1): num *= i return self.string.set(num); def clearall(self): self.string.set("") def equals(self): result = "" try: if self.string.get().find('!')==True: self.fac() result = eval(self.string.get()) self.string.set(result) except: result = "无效输入" self.string.set(result) def addChar(self, char): i = ['log', 'sqrt', 'pi', 'sin', 'cos', 'tan', 'e', "gcd", "radians", "degrees", "ceil", "hypot"] if char in i: self.string.set(self.string.get() + 'math.' + (str(char))) print("addchar的if语句"+self.string.get().format(()) + " " + str(char)) else: self.string.set(self.string.get() + (str(char))) print("addchar的else语句"+self.string.get() + " " + str(char)) def delete(self): self.string.set(self.string.get()[0:-1]) calculator() 源码下载 🚗

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本文标签： 阶乘计算器科学Python